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1.计算日期到天数的转换(简单)
计算日期到天数转换__牛客网 (nowcoder.com)
这题主要考察对闰年平年的判断，大家肯定能轻松解决的！！！
#include <stdio.h>int main() {int y, m, d;scanf("%d %d %d", &y, &m, &d);//判断是否为闰年int arr[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};if (((y % 4 == 0) && (y % 100 != 0)) || y % 400 == 0) {arr[1] = 29;}//求和int sum = 0;for (int i = 0; i < m - 1; i++) {sum += arr[i];}sum += d;printf("%d", sum);return 0;}2.日期差值(简单)
日期差值__牛客网 (nowcoder.com)
本题我采用的是年月分别求和(y1为最大值)，计算两个的年份的差值(单独计算)，求和他们本年的天数，sum求和；
相信大家会有更方便的方法的！！！
#include <stdio.h>void swap(int* x, int* y) {int tmp = *x;*x = *y;*y = tmp;
}int main() {int y1, m1, d1, y2, m2, d2;int arr[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };scanf("%4d%2d%2d", &y1, &m1, &d1);scanf("%4d%2d%2d", &y2, &m2, &d2);int sum2 = 0;int sum1 = 0;//因为后面我认为y1为大值，所以在这里判断将y1设置为大值if (y1 < y2) {swap(&y1, &y2);swap(&m1, &m2);swap(&d1, &d2);}if (y1 == y2) {if (m1 < m2) {swap(&m1, &m2);swap(&d1, &d2);}}if (y1 == y2) {if (m1 == m2) {if (d1 < d2) {swap(&d1, &d2);}}}//差的年数int x = y1 - y2;//记录y2年的天数if (((y2 % 4 == 0) && (y2 % 100 != 0)) || y2 % 400 == 0) {//判断是否为闰年arr[1] = 29;}for (int i = 0; i < m2 - 1; i++) {sum2 += arr[i];}sum2 += d2;//记录y1年的天数if (((y1 % 4 == 0) && (y1 % 100 != 0)) || y1 % 400 == 0) {//判断是否为闰年arr[1] = 29;}for (int i = 0; i < m1 - 1; i++) {sum1 += arr[i];}sum1 += d1;for (int i = 0; i < x; i++) {if (((y1 % 4 == 0) && (y1 % 100 != 0)) || y1 % 400 == 0) {sum1 += 366;} else {sum1 += 365;}}printf("%d", sum1 - sum2+1);return 0;
}3.日期累加
日期累加__牛客网 (nowcoder.com)
本题主要处理进位的问题，注意本题的打印格式
#include <iostream>
using namespace std;static int arr[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };int main() {int n;scanf("%d", &n);while (n--) {int y, m, d, add;//将年月日分别取值，以便后续分别处理scanf("%4d%2d%2d", &y, &m, &d);scanf("%d", &add);d += add;//将日相加if ((y % 4 == 0 && y % 100 != 0) || (y % 400 == 0)) {arr[2] = 29;}//判断是否超过当月的天数while (d > arr[m]) {if ((y % 4 == 0 && y % 100 != 0) || (y % 400 == 0)) {arr[2] = 29;} else {arr[2] = 28;}d -= arr[m];m++;while (m > 12) {m -= 12;y++;}}//因为对打印的值有特殊要求，这里需要特殊处理if (m > 9)if (d > 9) {printf("%d-%d-%d\n", y, m, d);} else {printf("%d-%d-0%d\n", y, m, d);} else{ if (d > 9) {printf("%d-0%d-%d\n", y, m, d);} else {printf("%d-0%d-0%d\n", y, m, d);}}}
}
