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Exercise2.60

We specified that a set would be represented as a list with no duplicates. Now suppose we allow duplicates. For instance, the set {1, 2, 3} could be represented as the list (2 3 2 1 3 2 2). Design procedures element of-set?, adjoin-set, union-set, and intersection-set that operate on this representation. How does the efficiency of each compare with the corresponding procedure for the non-duplicate representation? Are there applications for which you would use this representation in preference to the nonduplicate one?

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这道题目我有点没理解，如果允许重复的话，交集该怎么处理？所以最后交集我没有改变，element-of-set? 也没有修改。

(define (element-of-set? x set)(cond ((null? set) false)((equal? x (car set)) true)(else (element-of-set? x (cdr set)))))(define (adjoin-set x set)(cons x set))(define (union-set set1 set2)(append set1 set2))(define (intersection-set set1 set2)(cond ((or (null? set1) (null? set2)) '())((element-of-set? (car set1) set2)(cons (car set1) (intersection-set (cdr set1) set2)))(else (intersection-set (cdr set1) set2))))(define set1 (list 1 3 5 'a 'b 'c))
(define set2 (list 2 4 6 'a 'd 'c))(adjoin-set 'a set1)
(union-set set1 set2)
(intersection-set set1 set2); 执行结果
'{a 1 3 5 a b c}
'{1 3 5 a b c 2 4 6 a d c}
'{a c}