1.Abstraction of objects and classes
1.1the_student_class
class Student:def __init__(self, name, number):self.name = nameself.scores = [0] * numberdef getName(self):return self.namedef getScore(self, i):if 1 <= i <= len(self.scores):return self.scores[i - 1]else:raise IndexError("Index out of range")def setScore(self, i, score):if 1 <= i <= len(self.scores):self.scores[i - 1] = scoreelse:raise IndexError("Index out of range")def getAverage(self):return sum(self.scores) / len(self.scores)def getHighScore(self):return max(self.scores)def __str__(self):score_str = " ".join(str(score) for score in self.scores)return f"Name: {self.name}\nScores: {score_str}"
1.2library_borrow_system
class Book:def __init__(self, title, author, year):self.title = titleself.author = authorself.year = yearself.status = "Available" # 将初始状态改为 "Available"，与测试用例输出更匹配def check_out(self):if self.status == "Checked out ":print(f'"{self.title}" is already checked out.')else:self.status = "Checked out "print(f'"{self.title}" has been checked out.')def return_book(self):if self.status == "Available":print(f'"{self.title}" was not checked out.')else:self.status = "Available"print(f'"{self.title}" has been returned.')class Library:def __init__(self):self.books = []def add_book(self, book):self.books.append(book)def list_books(self):for book in self.books:print(f'"{book.title}" by {book.author} ({book.year}) - {book.status}')
2.function
2.1anagram_checker
def prompt_get_strings():print('Enter two strings and I\'ll tell you if they are anagrams: ')def get_first_string():while True:first_string = input('Enter the first string: ')cleaned_first_string = ''.join(char.lower() for char in first_string if char.isalpha())if cleaned_first_string and len(cleaned_first_string) > 1:return cleaned_first_stringelse:print('A valid input is required')def get_second_string():while True:second_string = input('Enter the second string: ')cleaned_second_string = ''.join(char.lower() for char in second_string if char.isalpha())if cleaned_second_string and len(cleaned_second_string) > 1:return cleaned_second_stringelse:print('A valid input is required')def is_anagram(first_string, second_string):sorted_first = sorted(first_string)sorted_second = sorted(second_string)return sorted_first == sorted_seconddef print_is_anagram(first_string, second_string):if is_anagram(first_string, second_string):print(f'{first_string} and {second_string} are anagrams.')else:print(f'{first_string} and {second_string} are not anagrams.')if __name__ == "__main__":prompt_get_strings()first_string = get_first_string()second_string = get_second_string()print_is_anagram(first_string, second_string)
2.2pay_off_credit_card
import math# 获取有效的信用卡偿还余额函数
def get_balance():while True:try:balance = int(input('What is your loan balance? '))return balanceexcept ValueError:print('A valid input is required')# 获取有效的年利率 APR 函数，APR 必须为整数
def get_apr():while True:try:apr = int(input('What is the APR on the loan (as a percent)? '))return aprexcept ValueError:print('A valid input is required')# 获取有效的月偿还额整数函数
def get_monthly_payments():while True:try:monthly_payment = int(input('What are the monthly payment you can make? '))return monthly_paymentexcept ValueError:print('A valid input is required')# 计算还清需要月份数函数
def calculate_months_until_paid_off(balance, apr, monthly_payment):daily_rate = apr / 100 / 365monthly_rate = (1 + daily_rate)**30 - 1n = -1 * math.log(1 - balance * monthly_rate / monthly_payment) / math.log(1 + monthly_rate)return math.ceil(n)# 打印还清需要月份信息函数
def print_months_take_to_pay(months):print(f'It will take you {months} months to pay off this loan')if __name__ == "__main__":balance = get_balance()apr = get_apr()monthly_payment = get_monthly_payments()months_until_paid_off = calculate_months_until_paid_off(balance, apr, monthly_payment)print_months_take_to_pay(months_until_paid_off)
2.3password_strength_indicator
# 导入正则库
import re# 定义获取有效密码的函数，输入密码长度不小于1
def get_password():while True:password = input('Enter password: ')if len(password) >= 1: # 补充代码判定输入密码长度不小于1return passwordelse:print('The password length must be at least 1.')# 定义判断密码强度等级并打印输出判断结果的函数
def password_validator(password):# 定义包含不同字符类别的标识 has_lower = re.search(r'[a-z]', password) is not None # 含小写字母has_upper = re.search(r'[A-Z]', password) is not None # 含大写字母has_digit = re.search(r'[0-9]', password) is not None # 含数字has_special = re.search(r'[!@#$%^&*(),.?":{}|<>]', password) is not None # 这些是特殊字符if len(password) <8 and password.isdigit():# 补充代码实现8位以下全数字是非常弱密码的判断条件print(f'The password \'{password}\' is a very weak password')elif len(password) < 8 and not password.isdigit(): # 补充代码实现8位以下有数字外字符是弱密码的判断条件print(f'The password \'{password}\' is a weak password')elif len(password) >= 8 and has_digit and (has_lower or has_upper) and not has_special:# 补充代码实现不少于8位含字母、数字，不含特殊字符是强密码的判断条件print(f'The password \'{password}\' is a strong password')elif len(password) >= 8 and has_digit and (has_lower or has_upper) and has_special:# 补充代码实现不少于8位含字母、数字、特殊字符是非常强密码的判断条件print(f'The password \'{password}\' is a very strong password')else:print("Unable to determine the strength level")if __name__ == "__main__": password = get_password()password_validator(password)
