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Day8

344.反转字符串

class Solution {
public:void reverseString(vector<char>& s) {int i = 0, j = s.size() - 1;char tmp;while(i < j){//这里用swap(A, B)可以让代码更加简洁tmp = s[i];s[i] = s[j];s[j] = tmp;i++;j--;}}
};

541. 反转字符串II

class Solution {
public:string reverseStr(string s, int k) {for(int i = 0; i < s.size(); i += (2 * k)){if(i + k <= s.size()){reverse(s.begin() + i, s.begin() + i + k);}else{reverse(s.begin() + i, s.end());}}return s;}
};